The observed frequency of the GA haplotype, P , is 3 out of 7, which equals 0.429. PAB – pApB equals 0.429 – 0.368 = 0.061= D. D is different than 0, so population is in linkage disequilibrium for the given haplotypes at the positions 29 and 33.

Z390 vs z490The frequency of a recessive allele a is 0.6. If a population is in Hardy-Weinberg equilibrium, what is the frequency of the dominant phenotype? This question is a bit confusing to me. I'm not sure how to use my knowledge about Hardy-Weinberg in this problem. I know that when q = 0.6, p = 1 - 0.6 = 0.4.

Let the allele frequencies in the four populations be denoted , , , and , respectively, and the vector of all four frequencies be . We want to write down a joint distribution for given the tree. We start by writing down the covariance between any two populations with respect to the ancestral allele frequency (i.e...